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Find the workrequired to be done to increase the volume of a bubble of soap solution having a radius1mm to 8 times . (surface tension of soap solution is 30 dyne cm^(-1)) |
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Answer» SOLUTION :INITIAL volume `V_(1)` and radius `R_(1)` New volume will be `V_(2)` `R_(1)=1CM,T=30" dyne"//cm` `V_(2)=8V_(1)W=?` Now `V_(2)=8V_(1)` `therefore(4)/(3)piR_(2)^(3)=8((4)/(3)piR_(1)^(3))` `thereforeR_(2)^(3)=(2R_(1))^(3)` `thereforeR_(2)=2R_(1)` Now `W=DeltaA*T=8piT[R_(2)^(2)-R_(1)^(2)]` `=8piT[4R_(1)^(2)-R_(1)^(2)]=24piTR_(1)^(2)` `=24xx3.14xx30xx1` `thereforeW=2261erg` |
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