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Find the zeroes of the polynomial `x^2-3`and verify the relationship between the zeroes and the coefficients. |
Answer» `P(x)=x^2-3` `x^2-3=0` `(x)^2-(sqrt3)^2` `(x-sqrt3)(x+sqrt3)=0` `x=sqrt3,-sqrt3` `alpha=sqrt3,beta=-sqrt3` `alpha+beta=sqrt3-sqrt3=0` `alpha*beta=sqrt3(-sqrt3)=-3` `ax^2+bx+c=0` `alpha+beta=-b/a=-(0)/1=0` `alpha*beta=c/a=(-3)/1=-3` |
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