1.

Find the zeroes of the quadratic polynomial f(x) = 6x2 – 3.

Answer»

To find the zeroes of the quadratic polynomial we will equate f(x) to 0 

∴f(x) = 0 

⇒ 6x2 – 3 = 0 

⇒ 3(2x2 – 1) = 0 

⇒ 2x2 – 1 = 0 

⇒ 2x2 = 1 

⇒ x2\(\frac{1}2\)

⇒ x = ± \(\frac{1}{\sqrt2}\) 

Hence, 

the zeroes of the quadratic polynomial f(x) = 6x2 – 3 are \(\frac{1}{\sqrt2}\), - \(\frac{1}{\sqrt2}\)



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