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Find the zeroes of the quadratic polynomial f(x) = 6x2 – 3. |
Answer» To find the zeroes of the quadratic polynomial we will equate f(x) to 0 ∴f(x) = 0 ⇒ 6x2 – 3 = 0 ⇒ 3(2x2 – 1) = 0 ⇒ 2x2 – 1 = 0 ⇒ 2x2 = 1 ⇒ x2 = \(\frac{1}2\) ⇒ x = ± \(\frac{1}{\sqrt2}\) Hence, the zeroes of the quadratic polynomial f(x) = 6x2 – 3 are \(\frac{1}{\sqrt2}\), - \(\frac{1}{\sqrt2}\) |
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