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Find the zeroes of the quadratic polynomial. Find the sum and product of the zeroes and verify relationship to the coefficients of terms in the polynomial.p(x) = x2 – 4 |
Answer» Given polynomial p(x) = x2 – 4 We have, x2 – 4 = (x – 2) (x + 2) So, the value of x2 – 4 is zero when x – 2 = 0 or x + 2 = 0 i.e., x = 2 or x = – 2 So the zeroes of x2 – 4 are 2 and – 2 ∴ Sum of the zeroes = 2 + (- 2) = 0 \(=-\frac{Coefficient\,of\,x}{Coefficient\,of\,x^2}= \frac{-0}{1}=1\) And product of the zeroes = 2 × (-2) = -4 \(=\frac{Consatnt\,term}{Coefficient\,of\,x^2}=\frac{-4}{1}=-4\) |
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