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Find the zeroes of the quadratic polynomial x2 - 6x + 8. |
Answer» Equating the expression with 0, x2 - 6x + 8 = 0 On factorising it further, x2 - 4x - 2x + 8 = 0 x(x - 4) – 2(x - 4) = 0 (x - 4) (x - 2) = 0 ∴ x = 4 or x = 2 ∴ The zeroes of x2 - 6x + 8 are 4 & 2. |
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