Find the zeroes of (x-2)²-(x+2)²

1.	Find the zeroes of (x-2)²-(x+2)²
Answer» (x-2)²-(x+2)²= (x - 2 + x + 2)(x - 2 - x - 2)= (2x)(-4)= -8xSo the zeroes of the polynomial is x = 0

Discussion