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Find the zeros of quadratic polynomials and verify the relationship between the zeros and their coefficients:f(v) = v2 + 4√3v – 15 |
Answer» Given, f(v) = v2 + 4√3v – 15 We put f(v) = 0 ⇒ v2 + 4√3v – 15 = 0 ⇒ v2 + 5√3v – √3v – 15 = 0 ⇒ v(v + 5√3) – √3 (v + 5√3) = 0 ⇒ (v – √3)(v + 5√3) = 0 This gives us 2 zeros, for v = √3 and v = -5√3 Hence, the zeros of the quadratic equation are √3 and -5√3. Now, for verification Sum of zeros = – coefficient of v / coefficient of v2 √3 + (-5√3) = – (4√3) / 1 -4√3 = -4√3 Product of roots = constant / coefficient of v2 √3 x (-5√3) = (-15) / 1 -5 x 3 = -15 -15 = -15 Therefore, the relationship between zeros and their coefficients is verified. |
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