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Find the zeros of quadratic polynomials and verify the relationship between the zeros and their coefficients:g(x) = a(x2 + 1) –x (a2 + 1) |
Answer» Given, g(x) = a(x2+1) – x(a2+1) We put g(x) = 0 ⇒ a(x2+1)–x(a2+1) = 0 ⇒ ax2 + a − a2x – x = 0 ⇒ ax2 − a2x – x + a = 0 ⇒ ax(x − a) − 1(x – a) = 0 ⇒ (x – a)(ax – 1) = 0 This gives us 2 zeros, for x = a and x = 1/a Hence, the zeros of the quadratic equation are a and 1/a. Now, for verification Sum of zeros = – coefficient of x / coefficient of x2 a + 1/a = – (-(a2 + 1)) / a (a2 + 1)/a = (a2 + 1)/a Product of roots = constant / coefficient of x2 a x 1/a = a / a 1 = 1 Therefore, the relationship between zeros and their coefficients is verified. |
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