1.

Find the zeros of quadratic polynomials and verify the relationship between the zeros and their coefficients:q(y) = 7y2 – (11/3)y – 2/3

Answer»

Given, 

q(y) = 7y2 – (11/3)y – 2/3 

We put q(y) = 0 

⇒ 7y2 – (11/3)y – 2/3 = 0 

⇒  (21y2 – 11y -2)/3 = 0 

⇒ 21y2 – 11y – 2 = 0 

⇒ 21y2 – 14y + 3y – 2 = 0

 ⇒ 7y(3y – 2) – 1(3y + 2) = 0 

⇒ (3y – 2)(7y + 1) = 0 

This gives us 2 zeros, for 

y = 2/3 and y = -1/7 

Hence, the zeros of the quadratic equation are 2/3 and -1/7. 

Now, for verification 

Sum of zeros = – coefficient of y / coefficient of y2 

2/3 + (-1/7) = – (-11/3) / 7 

-11/21 = -11/21 

Product of roots = constant / coefficient of y2 

2/3 x (-1/7) = (-2/3) / 7 

– 2/21 = -2/21 

Therefore, the relationship between zeros and their coefficients is verified.



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