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Find the zeros of the quadratic polynomial x2 +7x+10 and verify the relationshipbetween the zeros and the coefficients. |
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Answer» x²+7x+10=0 x²+2x+5x+10=0 x(x+2)+5(x+2)=0 (x+2)(x+5) = 0 x+2 = 0 ; x = -2 x+5 = 0 ; x = -5 Relationship between the zeroes and coefficients :- Sum of zeroes = -2+(-5) = -2-5 = -7/1 = -x coefficient /x² coefficient Product of zeroes = (-2)(-5) = 10/1 = constant/x² coefficient Hope it helps |
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