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Find the zeros of the quadratic polynomials 4x2 – 4x + 1 and verify the relationship between the zeros and the coefficients. |
Answer» Let f(x) = 4x2 ˗ 4x + 1 = (2x2) – 2(2x)(1) + (1)^2 = (2x – 1)2 To find the zeroes, set f(x) = 0 (2x – 1)2 = 0 x = 1/2 or x = 1/2 Again, Sum of zeroes = 1/2+1/2=1=1/1 = -b/a = (-Coefficient of x) / (Cofficient of x2) Product of zeroes = 1/2 x 1/2=1/4 = c/a = Constant term / Coefficient of x2 |
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