1.

Find the zeros of the quadratic polynomials 4x2 – 4x + 1 and verify the relationship between the zeros and the coefficients.

Answer»

Let f(x) = 4x2 ˗ 4x + 1

= (2x2) – 2(2x)(1) + (1)^2

= (2x – 1)2

To find the zeroes, set f(x) = 0

(2x – 1)2 = 0

x = 1/2 or x = 1/2

Again,

Sum of zeroes = 1/2+1/2=1=1/1

= -b/a

= (-Coefficient of x) / (Cofficient of x2)

Product of zeroes = 1/2 x 1/2=1/4

= c/a

= Constant term / Coefficient of x2



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