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Find the zeros of the quadratic polynomials 5x2 - 4 - 8x and verify the relationship between the zeros and the coefficients. |
Answer» Let f(x) = 5x2 ˗ 4 ˗ 8x = 5x2 ˗ 8x ˗ 4 = 5x2 ˗ (10x ˗ 2x) ˗ 4 = 5x2 ˗ 10x + 2x ˗ 4 = 5x (x ˗ 2) + 2(x ˗ 2) = (5x + 2) (x ˗ 2) To find the zeroes, set f(x) = 0 (5x + 2) (x ˗ 2) = 0 5x + 2 = 0 or x ˗ 2 = 0 x = (−2)/5 or x = 2 Again, Sum of zeroes = (-2)/5 + 2 = (-2+10)/5 = 8/5 = -b/a = (-Coefficient of x)/(Cofficient of x2) Product of zeroes = (-2/5) x 2 = (-4)/5 = c/a = Constant term / Coefficient of x2 |
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