Find the zeros of the quadratic polynomials x2 - 2x - 8 and verif

1.	Find the zeros of the quadratic polynomials x2 - 2x - 8 and verify the relationship between the zeros and the coefficients.
Answer» Let f(x) = x² ˗ 2x ˗ 8 = x² ˗ 4x + 2x ˗ 8 = x(x ˗ 4) + 2(x ˗ 4) = (x ˗ 4) (x + 2) To find the zeroes, set f(x) = 0, then either (x ˗ 4) = 0 or (x+2) = 0 x = 4 or x = -2 Again, Sum of zeroes = (4 – 2) = 2 = 2/1 = -b/a = (-Coefficient of x)/(Cofficient of x²) Product of zeroes = (4) (-2) = -8/1 = c/a = Constant term / Coefficient of x²

Find the zeros of the quadratic polynomials x2 - 2x - 8 and verify the relationship between the zeros and the coefficients.

Answer»

Let f(x) = x² ˗ 2x ˗ 8

= x² ˗ 4x + 2x ˗ 8

= x(x ˗ 4) + 2(x ˗ 4)

= (x ˗ 4) (x + 2)

To find the zeroes, set f(x) = 0, then

either (x ˗ 4) = 0 or (x+2) = 0

x = 4 or x = -2

Again,

Sum of zeroes = (4 – 2) = 2 = 2/1

= -b/a

= (-Coefficient of x)/(Cofficient of x²)

Product of zeroes = (4) (-2) = -8/1

= c/a

= Constant term / Coefficient of x²