Find three consecutive numbers such that if they are divided by 10, 17, and 26 respectively, the sum of their quotients will be 10.(Hint: Let the consecutive numbers = x , x + 1,x+2, thenx. x + x + 2++10 17 26= 10)

Find three consecutive numbers such that if they are divided by 10, 17

1.	Find three consecutive numbers such that if they are divided by 10, 17, and 26 respectively, the sum of their quotients will be 10.(Hint: Let the consecutive numbers = x , x + 1,x+2, thenx. x + x + 2++10 17 26= 10)
Answer» LET X, (X+1), (X+2) are 3 consecutive numbers.X/10 + (X+1)/17+ (X+2)/26 =10L.C.M = 4420(442(X) +260(X+1) +170(X+2))/4420=10(442x+260x+260+70x+340)= 4420×10(442x+260x+170x+260+340)=44200872x + 600= 44200872x= 44200- 600872x= 43600X= 43600/872X= 50Ist no. (X)= 50Ist no. (X)= 502nd no.(x+1)= 50+1= 51Ist no. (X)= 502nd no.(x+1)= 50+1= 513rd no.(x+2)= 50+2=52The 3 consecutive numbers are 50, 51, 52Hope this will help you...MARK as brainliestitz HAIFA..❤❤