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Find three rational numbers lying between 3/5 and 7/8

Answer» Here, 3/5 < 7/8.So, let y = 7/8, x = 3/5 & n = 3Since, d = y - x ÷ n + 1•7/8 - 3/5 ÷ 3 + 1 => 35-24/40 ÷ 4=> 11/40 ÷4=> 11/160.Now, three rational numbers :•(x+d), (x+2d), (x+3d)=> (3/5 + 11/160), (3/5 + 12/160), (3/5 + 13/160)=> (96+11/160), (96+12/160), (96+13/160)=> 107/160, 108/160, 109/160.
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Now i am saw you the second trick was it also realted to it Firstly it was formula:D=y-x/n+1(x+d) (x+2d) (x+3d)
First of all you will make same the denominater take LCM and now you can give between three numbers lyes between them


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