Find two consecutive positive integers sum of whose squares is 365.

1.	Find two consecutive positive integers sum of whose squares is 365.
Answer» Let two consecutive positive integers be x and x + 1 ∴ x²+ (x + 1)²= 365 ⇒ x² + x -182 = 0 (x +14) (x -13) = 0 ∴ x = 13 Hence two consecutive positive integers are 13 and 14

Answer»

Let two consecutive positive integers be x and x + 1

∴ x²+ (x + 1)²= 365

⇒ x² + x -182 = 0

(x +14) (x -13) = 0

∴ x = 13

Hence two consecutive positive integers are 13 and 14

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Find two consecutive positive integers sum of whose squares is 365.

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