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Find two consecutive positive integers sum of whose squares is 365. |
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Answer» Let two consecutive positive integers be `x and x+1` `" " therefore x^(2) + (x+1)^(2) = 365` `rArr x^(2) + x- 182=0` `" " (x + 14) (x - 13)=0` `" " therefore x = 13` Hence two consecutive positive integers are 13 and 14 |
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