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Find two consecutive positiveintegers, sum of whose squares is 365. |
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Answer» Correct Answer - 13 and 14 `x^(2)+(x+1)^(2)=365implies2x^(2)+2x-364=0impliesx^(2)+x-182=0` `:." "x^(2)+14x-13x-182=0.` |
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