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Find two irrational numbers lying between 0.1 and 0.12. |
Answer» Let, a = 0.1 = 0.10 And, b = 0.12 We observe that in the second decimal place a has digit 0 and b has digit 2. Therefore a < b. So, if we consider irrational numbers x = 0.11011001100011… y = 0.111011110111110… We find that, a < x < y < b Hence, x and y are required irrational numbers. |
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