1.

Find two numbers such that the sum of twice the first and thrice the second is 89 and four times the first exceeds five times the second by 13.

Answer»

Let the two numbers be x and y.

Then, equation formed are 2x + 3y = 89 ....(i)

4x - 5y = 13 ...(ii)

On solving eq. (i) & (ii) we get

x = 22

y = 15

Hence required numbers are 22 & 15.



Discussion

No Comment Found