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Find two numbers such that the sum of twice the first and thrice the second is 89 and four times the first exceeds five times the second by 13. |
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Answer» Let the two numbers be x and y. Then, equation formed are 2x + 3y = 89 ....(i) 4x - 5y = 13 ...(ii) On solving eq. (i) & (ii) we get x = 22 y = 15 Hence required numbers are 22 & 15. |
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