1.

Find x in each of the following:(i) 1/4! + 1/5! = x/6!(ii) x/10! = 1/8! + 1/9!(iii) 1/6! + 1/7! = x/8!

Answer»

(i) 1/4! + 1/5! = x/6!

As we know that

5! = 5 × 4 × 3 × 2 × 1

6! = 6 × 5 × 4 × 3 × 2 × 1

Therefore by using these values,

1/4! + 1/5! = x/6!

1/4! + 1/(5×4!) = x/6!

(5 + 1) / (5×4!) = x/6!

6/5! = x/(6×5!)

x = (6 × 6 × 5!)/5!

= 36

Thus, the value of x is 36.

(ii) x/10! = 1/8! + 1/9!

As we know that

10! = 10 × 9!

9! = 9 × 8!

Therefore by using these values,

x/10! = 1/8! + 1/9!

x/10! = 1/8! + 1/(9 × 8!)

x/10! = (9 + 1)/(9 × 8!)

x/10! = 10/9!

x/(10 × 9!) = 10/9!

x = (10 × 10 × 9!)/9!

= 10 × 10

= 100

∴ The value of x is 100.

(iii) 1/6! + 1/7! = x/8!

As we know that

8! = 8 × 7 × 6!

7! = 7 × 6!

Therefore by using these values,

1/6! + 1/7! = x/8!

1/6! + 1/(7 × 6!) = x/8!

(1 + 7)/(7 × 6!) = x/8!

8/7! = x/8!

8/7! = x/(8 × 7!)

x = (8 × 8 × 7!)/7!

= 8 × 8

= 64

Hence, the value of x is 64.



Discussion

No Comment Found

Related InterviewSolutions