1.

Find x in the following proportions:(i) 16: 18 = x: 96(ii) x: 92 = 87: 116

Answer»

(i) Given 16: 18 = x: 96

In proportion we know that product of extremes = product of means

16/18 = x/96

On cross multiplying

x = (18 × 96)/ 16

x = 256/3

(ii) Given x: 92 = 87: 116

In proportion we know that product of extremes = product of means

x/ 92 = 87/116

On cross multiplying

x = (87 × 92)/ 116

x = 69



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