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Find x in the following proportions:(i) 16: 18 = x: 96(ii) x: 92 = 87: 116 |
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Answer» (i) Given 16: 18 = x: 96 In proportion we know that product of extremes = product of means 16/18 = x/96 On cross multiplying x = (18 × 96)/ 16 x = 256/3 (ii) Given x: 92 = 87: 116 In proportion we know that product of extremes = product of means x/ 92 = 87/116 On cross multiplying x = (87 × 92)/ 116 x = 69 |
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