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Find zeroes of 2x2 - √2x + 1 = 0. |
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Answer» 2x2 - √2x + 1 = 0 ⇒ x = \(\frac{-(-\sqrt2)\pm\sqrt{2-8}}4\) = \(\frac{\sqrt2\pm\sqrt 6i}4\)(∵ i = √-1) Roots are \(\frac{\sqrt2-\sqrt6i}4\) or \(\frac{\sqrt2+\sqrt6i}4\) No real root exist |
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