Find zeroes of a polynomial x2 – 18x + 12 – InterviewSolution

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1.

Find zeroes of a polynomial x2 – 18x + 12

Answer»

9+√69,9-√69 is the correct answer of the given question

x^2-18x+12=+18+-V(18)^2-4(1)(12)/2(1)=+18+-V324-4(12)/2=18+-V324-48/2=18+-V276/2=9+-V138; 9+V138; 9-V138

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