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Find zeros of polynomial `x^2-5` and verify the relationship between zero and coefficients. |
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Answer» `x^2-5=0` `x=pmsqrt5` `x=sqrt5,-sqrt5` `x^2+(alpha+beta)x+alphabeta=0` `alpha+beta=sqrt5-sqrt5=0` `alpha*beta=sqrt5*sqrt5=-5` `x^2+0x+(-5)=0` `x^2`+(sum of roots)x+(product of roots)=0. |
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