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Findthe area of the region bounded by y= sinx, y = cosxand ordinatesx = 0, x = pi//2. |
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Answer» Solution :`UNDERSET(0)OVERSET(pi/2)INT|sinx-cosx|dx` `underset(0)overset(pi//4)int(cosx-sinx)dx + underset(pi//4)overset(pi//2)int(sinx-cosx) dx = 2(sqrt(2)-1)` |
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