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findthe resultantoftwoforceseachhavingmagnitudeF_0and anglebetweenthemistheta . |
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Answer» Solution :`F_("Resultant")^(2)=F_(0)^(2)+F_(0)^(2)+2F_(0)^(2) cos theta=2F_(0)^(2)(1+costheta)=2F_(0)^(2)(1+2"cos"^(2)( theta)/2-1)=F_(0)^(2)xx2"cos"^(2)(theta)/2` `F_("resultant")=2F_(0)"cos" (theta)/2` |
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