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First ionization potential of C-atom is greater than that of B-atom, where as the reverse is true for second ionization potential. |
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Answer» <P> Solution :`C(Z=6)1s^(2)2s^(2)2p_(x)^(1)2p_(y)^(1)`. The electron removal from p orbital is very difficult. So carbon has highest first IONIZATION potential.`B(Z=5)1s^(2)2s^(2)2p^(1)`. In boron nuclear charge is less that that of carbon, so boron has lowest first ionization potential. `I.E_(1)CgtI.E_(1)B` But it is reverse in the case of second ionization energy. Because in case `B^(+)` the electronic configuration is `1s^(2)2s^(2)`, which is completely FILLED and it has high ionization energy. But `C^(+)` the electronic configuration is `1s^(2)2s^(2)2p^(1)`, one electron removal is easy so it has ionization energy. `I.E_(2)BgtI.E_(2)C` |
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