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First of the two ideal gases has twice molar volume as much as the second at same temperature, what is the ratio of their pressures?(a) 4:1(b) 1:4(c) 2:1(d) 1:2This question was addressed to me during an online interview.The doubt is from Ideal Gas Law topic in division Recycle, Bypass, Purge, Ideal Gases and Real Gases of Basic Chemical Engineering |
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Answer» RIGHT OPTION is (d) 1:2 Explanation: P1V1 = n1RT1, P2V2 = n2RT2 dividing both the EQUATIONS, => P1:P2 = 1:2. |
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