InterviewSolution
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InterviewSolution
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Five cards – ten, jack, queen, king and an ace of diamonds are shuffled face downwards. One card is picked at random. (i) What is the probability that the card is a queen? (ii) If a king is drawn first and put aside, what is the probability that the second card picked up is the (a) ace? (b) king? |
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Answer» Total number of possible outcomes, n(S) = 5 (i) Number of events of drawing a queen, n(E) = 1 ∴ P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{1}{5}\) (ii) If a king is drawn first and put aside, total number of remaining cards, n(S) = 4 a) Probability that second card is ace, P(E) = \(\frac{n(E)}{n(S)}\) = \(\frac{1}{4}\) b) Since there was only a single king and when it is put aside, then n(E) = 0 ∴ P(E) = \(\frac{n(E)}{n(S)}\) = 0 |
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