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Five identical capacitor plates, each of area A, are arranged such that adjacent plates are at a distance d apart, the plates are connected to a source of emf V as shown in the figure The charge on plate 1 is ………..and on plate 4 is............. |
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Answer» The five plates make up four identical capacitors A,B,C,D, each of capacity `(in_(0) A//d)`, connected in parallel. As plate 1 is connected to `+` of battery and is a part of one capacitor only, therefore, charge on it is `q_(1) = +((in_(0) A)/(d)) V` However, plate 4 is connected to negaative of battery, and is common to two identical capacitors C and D is parallel, therefore, `q_(4) = -(q_(C) + q_(D)) = -2q_(1) = (-2 in_(0) A)/(d)` V |
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