Five kg of air is heated at constant volume. The temperature of air increase from 300K to 340K. If the specific heat at constant volume is 0.169 kcal/kg K, find the amount of heat absorbed.

Five kg of air is heated at constant volume. The temperature of air in

1.	Five kg of air is heated at constant volume. The temperature of air increase from 300K to 340K. If the specific heat at constant volume is 0.169 kcal/kg K, find the amount of heat absorbed.
Answer» Solution :`m=5kg,dT=340-300=40K` , `C_(v)=0.169 kcal/kg K`, PRINCIPAL specific heat at constant VOLUME `C_(v)=(DQ)/(mdT)` The amount of heat absorbed, `dQ=mC_(v)dT=5xx0.169xx40=33.8 kcal` .