Five kg of air is heated at constant volume. The temperature of air increases from 300K to 340 K. If the specific heatat constant volumeis 0.169 kcal/kg K, find the amount of heat absorbed.

Five kg of air is heated at constant volume. The temperature of air in

1.	Five kg of air is heated at constant volume. The temperature of air increases from 300K to 340 K. If the specific heatat constant volumeis 0.169 kcal/kg K, find the amount of heat absorbed.
Answer» Solution :`m = 5kg, DT = 340-300=40K`, `C_(v)=0.169 "kcal"//KG K`, Principal specific heat at constant volume `C_(v)=(dQ)/(MDT)` The amount of heat absorbed, `dQ=mC_(v) dT` `=5xx0.169 XX 40 = 33.8` kcal.