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Five years age a manwas seven times as old as his son. Five years hence, the father will be threetimes as old as his son. Find their present ages. |
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Answer» Let present age of son be x years and the present age of father by y years. Five years hence, the age of son = x + 5 and the age of father = y + 5 Using given information 3(x + 5) = y + 5 implies 3x - y = - 10 ….(1) Five years ago, age of son = (x - ) years and age of father = (y - 5) years `therefore 7(x - 5) = y - 5` implies 7x - y = 30 ...(2) Subtracting equation (1) from (2), we get 4x = 40 implies x = 10 On substituting x = 10 in equation (1) `3 xx 10 - y = - 10` implies 30 - y = - 10 implies - y = - 40 implies y = 40 Hence, present age of son is 10 years and present age of father is 40 years. |
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