Saved Bookmarks
| 1. |
fo, Bare the zeroes of the polynomial x' + 8x + 6, then find the quadratic polynomial wnese zeroes are notry-B and a+B &ав |
|
Answer» x²+8x+6here a=1,b=8,c=6if α,β are zeroes then α+β=-b/a=-8/1=-8αβ=c/a=6/1=6(iv)rewuired quadratic polynomial whose zeroes are x²-[α/β+β/β]x+α/β*β/α=0x²-[(α²+β²)/αβ]x+1=0x²-[(α+β)²-2αβ]x+1=0x²-[(-8)²-2(6)]x+1=0x²-(64-12)x+1=0thereforex²-52x+1=0is the required quadratic polynomial option c is the right answer let alpha = p, bita = qx^2+8x+6p+q= -8pq= 6(p-q)^2= (p+q)^2-4pq = 64-36= 28 p-q= 2√7sum of given zeros p-q+p+q= 2√7+-8product of given zeroes (p-q)(p+q)= 2√7× -8= -16√7polynomial=x^2-x(sum of zero)+product of zerox^2-x(2√7-8)+(-16√7)x^2-x(2√7-8)-16√7 |
|