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Follow my above account okk in a Trapezium ABCD AD=DC=BC=20cm angle A =60°find 1. length of AB2. DISTANCE BETWEEN AB and DC |
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Answer» assume a PERPENDICULAR to AB from D meets at F.we GET DF/AD = Sin60°so, DF = 20×√3/2 = 10√3. this is the DISTANCE between AB and DC.now AF = 10√3/tan60° = 10√3/√3 = 10.so, AB = 2×AF + DC = 2×10+20 = 40.Explanation: |
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