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Following are explain by reasons : The solution of strong base and weak acid salt is basic |
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Answer» Solution :The solution of `NaCH_3COO` (Sodium Acetate ) is basic : Sodium acetate is a salt of strong base NaOH and weak acid acetic acid `(CH_3COOH)` `CH_3COONa_((aq))hArr Na_((aq))^(+) +CH_3COO_((aq))^(-)` …. (a) CATION `Na^+` is not hydrolysed and REMAIN in solution as `Na_((aq))^(+)` . The acetate ion formed by ionization of sodium acetate is interactionwith water and dehydrolysis and produce weak acid `CH_3COOH` and `OH^-` ion. `CH_3COO_((aq))^(-) + H_2O_((l)) hArr CH_3COOH_((aq))+ OH_((aq))^(-)` ...(b) This `CH_3COOH` is a weak acid so remain as a dissociate molecule in solution. Thus `[OH^-]` increase in solution. Total REACTION of (a) and (b) : `CH_3COONa_((aq)) + H_2O_((l)) hArr ubrace(Na_((aq))^(+)+ OH_((aq))^(-))_(NaOH)+ CH_3COOH_((aq))` Thus concentration of `OH^-` in solution increase and solution BECOME basic . The pH of solution is more than `(pH gt 7)`. Similarly , all strong base and weak acid salts are basic. |
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