1.

Following cell is set up between copper and silver electrodes : Cu|Cu^(2)(aq)||Ag^(+)(aq)|(Ag) if its two half cells work under standard condition calculate the e.m.f of the cell ["Given" E_(Cu^(2+)/Cu)^(@)=0.34 "volt" E_(Ag^(+)/Ag=+0.80 "volt")^(@)]

Answer»


ANSWER :`E^(2)_("CELL")=E_("CATHODE")^(@)-E^(2)_("anode")=E_(Ag^(+)//Ag)^(@)-E_(Cu^(2+)//Cu)^(@)=+0.80-(+0.34)=0.46V`


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