Following data is given for the reacson, CaCO_(3(s))toCaO_((s))+CO_(2(s)) Delta_(f)H^(@)[CaO_((s))]=-650.0" kJ mol"^(-1) Delta_(f)H^(@)[CO_(2(g))]=-395.9" kJ mol"^(-1) Delta_(f)H^(@)[CaCO_(3(s))]=-1206.9" kJ mol"^(-1) Predict the effect of temperature on the equilibrium constant of the above reaction.

Following data is given for the reacson, CaCO_(3(s))toCaO_((s))+CO_(2

1.	Following data is given for the reacson, CaCO_(3(s))toCaO_((s))+CO_(2(s)) Delta_(f)H^(@)[CaO_((s))]=-650.0" kJ mol"^(-1) Delta_(f)H^(@)[CO_(2(g))]=-395.9" kJ mol"^(-1) Delta_(f)H^(@)[CaCO_(3(s))]=-1206.9" kJ mol"^(-1) Predict the effect of temperature on the equilibrium constant of the above reaction.
Answer» Solution :`CaCO_(3(s))toCaO_((s))+CO_(2(s))` `Delta_(f)H^(@)=Delta_(f)H^(@)[CaO_((s))]+Delta_(f)H^(@)[CO_(2(G))]-Delta_(f)H^(@)[CaCO_(3(s))]` `Delta_(f)H^(@)=-650+(395.9)-(-1206.9)` `=+161" kJ mol"^(-1)` Because `DELTAH` value is positive so the reaction is ENDOTHERMIC. Hence, according to Le-Chatelier's PRINCIPLE, reaction will proceed in forward direction on increasing temperature.