Following graph shows variation of ionization energies with atomis number in second period `(Li -Ne)`. Value of ionization energies of `Na(11)` will be- A. above `Ne`B. below `Ne` but above `O`C. below `Li`D. between `N` and `O`.

Following graph shows variation of ionization energies with atomis num

1.	Following graph shows variation of ionization energies with atomis number in second period `(Li -Ne)`. Value of ionization energies of `Na(11)` will be- A. above `Ne`B. below `Ne` but above `O`C. below `Li`D. between `N` and `O`.
Answer» `Na` is `3rd` period element and is bigger than `Li`. The distance between the nucleus and outer most electron is more as compared to `Li`. Thus the outer most electron is loosely bound with nucleus and removal of electron is easier. So option `(C )` is correct.

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Following graph shows variation of ionization energies with atomis number in second period `(Li -Ne)`. Value of ionization energies of `Na(11)` will be- A. above `Ne`B. below `Ne` but above `O`C. below `Li`D. between `N` and `O`.

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