1.

Following redox in balancing state has how many P, H, O and electric charge on left side respectively. P_(4)+OH^(1-)toPH_(3)+H_(2)PO_(2)^(-)

Answer»

<P>`4,1,1,-1`
`2,9,6,0`
`4,6,9,-3`
`4,9,6,-3`

SOLUTION :BALANCE reaction :
`P_(4)+3OH^(-)+3H_(2)OtoPH_(3)+3H_(2)PO_(2)^(-)`


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