1.

Following solutions were prepared by mixing different volumes of NaOH and HCl of different concentrations:(a) 60 ml, (M)/(10) HCl + 40 ml (M)/(10) NaOH (b) 55ml, (M)/(10) HCl +45 ml (M)/(10) NaOH (c) 75ml , M/5 HCl + 25ml M/5 NaOH (d) 100 ml, M/5 HCl + 100 ml (M)/(10) NaOH pH of which one of them will be equal to 1?

Answer»

c
b
d
a

Solution :`75ml M/5 HCl + 25 ml M/5 NAOH`
` THEREFORE (75-25) = 50ml M/5 + HCl` REMAIN
Total volume=100ml x m
`1/5 M xx 50 ml = 100 ml xx xm`
` therefore x= 1/5 xx 50 xx 1/100 = 1/10 M HCl =[H^+]`
` therefore PH = -log (1/10) = 1.0`


Discussion

No Comment Found