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Following solutions were prepared by mixing different volumes of NaOH and HCl of different concentrations:(a) 60 ml, (M)/(10) HCl + 40 ml (M)/(10) NaOH (b) 55ml, (M)/(10) HCl +45 ml (M)/(10) NaOH (c) 75ml , M/5 HCl + 25ml M/5 NaOH (d) 100 ml, M/5 HCl + 100 ml (M)/(10) NaOH pH of which one of them will be equal to 1? |
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Answer» c ` THEREFORE (75-25) = 50ml M/5 + HCl` REMAIN Total volume=100ml x m `1/5 M xx 50 ml = 100 ml xx xm` ` therefore x= 1/5 xx 50 xx 1/100 = 1/10 M HCl =[H^+]` ` therefore PH = -log (1/10) = 1.0` |
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