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For 6252 AT/Poles, if brush shift is of 2.50 mech. Degrees, what will be the cross-magnetizing ampere-turns per pole for a 6-pole DC machine?(a) 521(b) 5731(c) 5231(d) 571The question was asked during a job interview.I'd like to ask this question from Armature Reaction topic in portion Armature Reaction of DC Machines

Answer»

Right option is (b) 5731

For explanation: For calculations, from given mech. DEGREES SHIFT we NEED to find electrical degrees shift. Electrical shift= mechanical shift*(P/2). Thus, electrical shift is EQUAL to 7.50. Cross-magnetizing ampere-turns is given by 6250*(1-2*7.5/180) = 5731 AT/Pole.



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