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For 6252 AT/Poles, if brush shift is of 2.50 mech. Degrees, what will be the demagnetizing ampere-turns per pole for a 6-pole DC machine?(a) 521(b) 5731(c) 5231(d) 571This question was posed to me during an interview.This question is from Armature Reaction in section Armature Reaction of DC Machines |
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Answer» RIGHT choice is (a) 521 The BEST I can explain: From given MECH. Degrees shift we NEED to find electrical degrees shift. Electrical shift= mechanical shift*(P/2). Thus, electrical shift is equal to 7.50. Demagnetizing ampere-turns is given by 6250*(2*7.5/180) = 521 AT/Pole. |
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