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For a 3 phase 400V alternator supplying a load of 0.8 pf lagging at an armature current of 1.1pu. The power delivered to load is?(a) 0.88pu(b) 0.8pu(c) 0.66pu(d) 1.375puThe question was posed to me in a national level competition.My doubt is from Power Angle Characteristics of Synchronous Machines in portion Synchronous Machines of Electrical Machines

Answer»

The correct CHOICE is (C) 0.66pu

The explanation: P = EVsinδ/X = 1.1*1*sin36.67 = 6.6 pu.



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