1.

For a 3s- orbital Psi (3s) = 1/(9sqrt(3)) ((1)/(a_0))^(3//2) (6 - 6sigma + sigma^2)e^(-sigma//2), where sigma = (2rZ)/(3a_0) . What is the maximum radial distance of node from nucleus?

Answer»

`((3+ SQRT(3))a_0)/(z)`
`(a_0)/(z)`
`3/2 ((3+SQRT3)a_0)/(z)`
`(2a_0)/(z)`

Solution :At radial NODE `varphi^2 =0 , sigma^2 - 6 sigma + 6 =0`
`sigma = 3 + sqrt3 , r =3/2 ((3+sqrt3)/(2))a_0`


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