For a 3s− orbitalΨ(3s)=19√3(1a0)32(6−6σ+σ2)e−σ2;where σ=2 – InterviewSolution

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1.	For a 3s− orbitalΨ(3s)=19√3(1a0)32(6−6σ+σ2)e−σ2;where σ=2r.Z3a0What is the maxium radial distance of node from nucleus?
Answer» For a $3 s -$ orbital $Ψ (3 s) = \frac{1}{9 \sqrt{3}} {(\frac{1}{a_{0}})}^{\frac{3}{2}} (6 - 6 σ + σ^{2}) e^{\frac{- σ}{2}}; where σ = \frac{2 r . Z}{3 a_{0}}$ What is the maxium radial distance of node from nucleus?

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