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For a 4-pole, 50 Hz induction motor has starting current as 5 times to that of the full load current working at a speed of 1450rpm. The ratio of starting to full load torque will be?(a) 0.83(b) 0.17(c) 0.67(d) 1I have been asked this question in final exam.I want to ask this question from Starting of Polyphase Induction Motors-I in portion Starting of Induction Motors of Electrical Machines |
Answer» CORRECT ANSWER is (a) 0.83 Explanation: Tst/Tfl = (Ist/Ifl)^2*slip Tst/Tfl = 25*0.033 = 0.83 |
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