1.

For a body in `SHM` the velocity is given by the relation `V = sqrt(144-16x^(2))ms^(-1)`. The maximum acceleration isA. `12 m//s^(2)`B. `16 m//s^(2)`C. `36 m//s^(2)`D. `48 m//s^(2)`

Answer» Correct Answer - D
`a_(max) = omega^(2)A, V = omega sqrt(A^(2) -x^(2))`


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