InterviewSolution
Saved Bookmarks
| 1. |
For a body in `SHM` the velocity is given by the relation `V = sqrt(144-16x^(2))ms^(-1)`. The maximum acceleration isA. `12 m//s^(2)`B. `16 m//s^(2)`C. `36 m//s^(2)`D. `48 m//s^(2)` |
|
Answer» Correct Answer - D `a_(max) = omega^(2)A, V = omega sqrt(A^(2) -x^(2))` |
|