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For a CE- transistor amplifier , the audio signal voltage across the collector resistance of ` 2 k Omega ` is 2 V . Suppose the current amplifiaction factor of the transistor is 100 . Find the input signal voltage and base current , if the base resistance is `1 k Omega` . |
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Answer» Here, `R_(0)=2000Omega, V_(0)=2V, beta_(ac)=100, V_(i)=?I_=?, R_(i)=1000Omega` As, `A_(V)=V_(0)/V_(i)=beta_(ac)R_(0)/R_(i) or V_(i)V_(0)/(beta_(ac).(R_(0)//R_(i)))=2/(100(2000//1000))=0.01V` `I_=V_(i)/R_(i)=(0.01V)/(1000Omega)=10muA` |
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